The TME-EMT project
Short intervals containing primes
1. Interval with primes, without any congruence condition
The story seems to start in 1845 when Bertrand conjectured after
numerical trials
that the interval $]n,2n-3]$ contains a prime as soon as $n\ge4$. This was proved
by \v Ceby\v sev in 1852 in a famous work where he got the first good
quantitative estimates for the number of primes less than a given bound,
say $x$. By now, analytical means combined with sieve methods
(see
)
ensures us that each of the
intervals $[x,x+x^{0.525}]$ for $x \geq x_0$
contains at least one prime.
This statement concerns only for the (very) large integers.
It falls very close to what we can get under the assumption
of the Riemann
Hypothesis: the interval $[x-K\sqrt{x}\log x,x]$ contains a prime, where
$K$ is an effective large constant and $x$ is sufficiently large
(cf
for an account on this subject). A theorem
of Schoenfeld
also tells us that the interval
\begin{equation*}
[x-\sqrt{x}\log^2x/(4\pi),x]
\end{equation*}
contains a prime for $x\geq 599$ under the Riemann Hypothesis. These results
are still far from the conjecture in
on
probabilistic grounds: the interval $[x-K\log^2x,x]$ contains a prime for any
$K > 1$ and $x\geq x_0(K)$. Note that this statement has been proved for almost
all intervals in a quadratic average sense in
assuming the Riemann Hypothesis and replacing $K$ by a function $K(x)$ tending
arbitrarily slowly to infinity.
proved the following.
Theorem (1976)
Let $x$ be a real number larger than $2\,010\,760$. Then the interval
$$
\Bigl] x \Bigl(1-\frac1{16\,597}\Bigr),x \Bigr]
$$
contains at least one prime.
The main ingredient is the explicit formula and a numerical verification of
the Riemann hypothesis.
From a numerical point of view, the Riemann Hypothesis is known to hold up to
a very large height (and larger than in 1976).
and the Zeta grid
project verified this hypothesis till height $T_0=2.41\cdot 10^{11}$
and
till height $T_0=2.44 \cdot 10^{12}$
thus extending the work
who had conducted such a verification in 1986 till
height $5.45\times10^8$.
This latter computations has appeared in a refereed journal, but this is not
the case so far concerning the other computations; section 4 of the paper
casts some doubts on whether all the zeros where checked.
Discussions in 2012 with Dave Platt from the university of Bristol led me to
believe that the results of
can be replicated in a very rigorous setting, but that it may be difficult to
do so with the results of
with the
hardware at our disposal.
In
,
we used
the value $T_0=3.3 \cdot 10^{9}$ and obtained the following.
Theorem (2002)
Let $x$ be a real number larger than $10\,726\,905\,041$. Then the interval
$$
\Bigl] x \Bigl(1-\frac1{28\,314\,000}\Bigr),x \Bigr]
$$
contains at least one prime.
If one is interested in somewhat larger value, the paper
also
contains the following.
Theorem (2002)
Let $x$ be a real number larger than $\exp(53)$. Then the interval
$$
\Bigl] x \Bigl(1-\frac1{204\,879\,661}\Bigr),x \Bigr]
$$
contains at least one prime.
Increasing the lower bound in $x$ only improves the constant by less than 5
percent. If we rely on
,
we can prove
that
Theorem (2004, conditional)
Let $x$ be a real number larger than $\exp(60)$. Then the interval
$$
\Bigl] x \Bigl(1-\frac1{14\,500\,755\,538}\Bigr),x \Bigr]
$$
contains at least one prime.
Note that all prime gaps have been computed up
to $10^{15}$ in
, extending a
result of
.
In
,
we find
Theorem (2016)
Let $x$ be a real number larger than $2\,898\,242$. The interval
$$
\Bigl[ x, x \Bigl(1+\frac1{111(\log x)^2}\Bigr) \Bigr]
$$
contains at least one prime.
In
,
we find
Theorem (2016)
Let $x$ be a real number larger than $468\,991\,632$. The interval
$$
\Bigl[ x, x \Bigl(1+\frac1{5000(\log x)^2}\Bigr),x \Bigr]
$$
contains at least one prime.
Let $x$ be a real number larger than $89\,693$. The interval
$$
\Bigl[ x, x \Bigl(1+\frac1{\log^3 x}\Bigr) \Bigr]
$$
contains at least one prime.
The proof of these latter results has an asymptotical part, for $x\ge 10^{20}$ where we used the
numerical verification of the Riemann hypothesis together with two other
arguments: a (very strong) smoothing argument and a use of the Brun-Titchmarsh
inequality.
The second part is of algorithmic nature and covers the range $10^{10} \le x \le
10^{20}$ and uses prime generation
techniques
:
we only look at families of numbers whose primality can be established with
one or two Fermat-like or Pocklington's congruences. This kind of technique
has been already used in a quite similar problem in
.
The generation technique we
use relies on a theorem proven in
and enables us to generate dense
enough families for the upper part of the range to be investigated. For the
remaining (smaller) range, we use theorems of
that yield a fast primality test (for this limited range).
Let us recall here that a second line of approach following the original
work of \v Ceby\v sev is still under examination though it does not give
results as good
as analytical means (see
for the latest result).
For very large numbers
proved the following.
Theorem (2014)
The interval $(x,x+3 x^{2/3}]$ contains a prime for $x\ge \exp(\exp(34.32))$.
This is improved in
as follows.
Theorem (2021)
The interval $(x,x+3 x^{2/3}]$ contains a prime for $x\ge \exp(\exp(33.99))$.
2. Interval with primes under RH, without any congruence condition
Theorem (2002)
Under the Riemann Hypothesis, the interval $\bigl]x-\tfrac85\sqrt{x}\log x,x\bigr]$
contains a prime for $x\ge2$.
This is improved upon
in
into:
Theorem (2015)
Under the Riemann Hypothesis, the interval $\bigl]x-\tfrac4{\pi}\sqrt{x}\log x,x\bigr]$
contains a prime for $x\ge2$.
In , the authors go one step further and prove the next result.
Theorem (2019)
Under the Riemann Hypothesis, the interval $\bigl]x-\tfrac{22}{25}\sqrt{x}\log x,x\bigr]$
contains a prime for $x\ge4$.
3. Interval with primes, with congruence condition
Collecting references:
,
,
.
Last updated on September 1rst, 2021, by Charles Greathouse.